三角函数公式

\large \sin(0°)=0

\large \sin(30°)=\sin(\frac{\pi}{6})=\frac{1}{2}

\large \sin(45°)=\sin(\frac{\pi}{4})=\frac{\sqrt2}{2}

\large \sin(60°)=\sin(\frac{\pi}{3})=\frac{\sqrt3}{2}

\large \sin(90°)=\sin(\frac{\pi}{2})=1

\large \sin^2(A)+cos^2(A)=1

\large \tan(A)=\frac{\sin (A)}{\cos (A)}

\large \cot(A)=\frac{1}{\tan (A)}

\large \sec(A)=\frac{1}{cos (A)}

\large \csc(A)=\frac{1}{sin (A)}

\large \sin(2kπ+α)=sin (α)

\large \cos(2kπ+α)=cos (α)

\large \tan(kπ+α)=tan (α)

\large \sin(-α)=- \sin (α)

\large \cos(-α)= \cos (α)

\large \tan(-α)=- \tan (α)

\large \sin(π+α)=- \sin (α)

\large \cos(π+α)=- \cos (α)

\large \tan(π+α)=\tan (α)

\large \sin(π-α)= \sin (α)

\large \cos(π-α)=- \cos (α)

\large \tan(π-α)=- \tan (α)

\large \sin(\frac{(2k+1)\pi}{2}±α)=\cos (α)

\large \cos(\frac{(2k+1)\pi}{2}±α)= ∓\sin (α)

\large \tan(\frac{(2k+1)\pi}{2}±α)= ∓\cot (α)

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